The doubling time would be in an exponential expression,
that is:
x^y
where x is the quantity being doubled, and y is the doubling
times
Since it must be equal to 32 times the initial value,
therefore:
x^y = 32 x
x^y / x = 32
x^(y – 1) = 32
(y – 1) log x = log 32
y = (log32 / log x) + 1
x is the initial value, y is the doubling required
