Respuesta :

konrad509
[tex]f(x)=(x-2)^3+1\\ f'(x)=3(x-2)^2[/tex]

The derivative is always nonnegative, so it doesn't change sign, therefore there is no turning point.
asiafloren

Answer:

(2,4)

Step-by-step explanation:

add 3 and 1

change -2 ---> 2

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