AthenaMullet11
AthenaMullet11 AthenaMullet11
  • 12-08-2015
  • Mathematics
contestada

What is the simplified form of (cube root of)16

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apologiabiology
apologiabiology apologiabiology
  • 13-08-2015
remember that [tex] \sqrt[n]{x^m}= x^{ \frac{n}{m} } [/tex] so

∛16=16^(1/3)
we know that
16=2^3 so
(2^3)^(1/3)
remember another rule
(x^m)^n=x^(mn) so
(2^3)^(1/3)=2^(3/3)=2^1=2
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