stephebourbonoxou84 stephebourbonoxou84
  • 12-10-2017
  • Chemistry
contestada

A solution is created by dissolving 11.0 grams of ammonium chloride in enough water to make 305 mL of solution. How many moles of ammonium chloride are present in the resulting solution?

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Frankiometry1998
Frankiometry1998 Frankiometry1998
  • 13-10-2017
reacting mass=11.0
molar mass =53.45
moles=reacting Mass /molar mass
11.0/53.45=0.21moles
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