Maniac16
Maniac16 Maniac16
  • 13-10-2017
  • Mathematics
contestada

help!? i dont understand. First question on top, and second question in bottom

help i dont understand First question on top and second question in bottom class=

Respuesta :

WojtekR
WojtekR WojtekR
  • 13-10-2017
We know that:

[tex]$\sqrt[a]{x^b}=x^{\frac{b}{a}}[/tex]

so:

1)

[tex]$(\sqrt[3]{t^4})\cdot(t^{\frac{-1}{2}})=(t^{\frac{4}{3}})\cdot(t^{\frac{-1}{2}})= t^{\frac{4}{3}+\frac{-1}{2}}=t^{\frac{8}{6}+\frac{-3}{6}}=t^{\frac{8-3}{6}}=\boxed{t^{\frac{5}{6}}=\sqrt[6]{t^5}}[/tex]

2)

[tex]x^{-\frac{2}{5}}=\dfrac{1}{x^{\frac{2}{5}}}=\boxed{\dfrac{1}{\sqrt[5]{x^2}}}[/tex]

Answer 4)
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