keikolovesu
keikolovesu keikolovesu
  • 14-10-2015
  • Mathematics
contestada

what are 2 ways to solve 20=-5(-3+x)

Respuesta :

Аноним Аноним
  • 14-10-2015
1) First way:

[tex]-5(-3+x) = 20[/tex]

=> [tex]15 - 5x = 20[/tex]

=> [tex]-5x = 20 -15[/tex]

=> [tex]-5x = 5[/tex]

=> 
[tex]x = 5/-5[/tex]

=> 
[tex]x = -1[/tex]


2) Second way:

[tex]-5(-3+x)=20[/tex]

=> 
[tex]-3+x = 20/-5[/tex]

=> 
[tex]- 3 + x = -4[/tex]

=> 
[tex]x = -4 + 3[/tex]

=> 
[tex]x = -1[/tex]


Answer Link
mohammedmisfar mohammedmisfar
  • 14-10-2015
1) 20 = -5(-3+x)
20/-5 = -3 + x 
-4 = -3 + x
-4 + 3 = x
x = -1
2)20 = -5(-3 + x)
20 = 15 - 5x
20 - 15 = - 5x
5 = -5x
5/-5 = x
x = -1
Answer Link

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