Respuesta :

tomek1172
[tex]d=2r\\ d=22\\ 2r=22\\ r=11\ inches\\ \\ A=\pi r^2\\ A=\pi \cdot 11^2=3,14 \cdot 121=379,94\ inch^2[/tex]
D3xt3R
[tex]R=\frac{Diameter}{2}[/tex]

then

[tex]R=\frac{22~in}{2}[/tex]

[tex]\boxed{R=11~in}[/tex]

now we just need to apply this formula

[tex]S=\pi*R^2[/tex]

[tex]S=\pi*11^2[/tex]

[tex]\boxed{\boxed{S=121*\pi~in^2}}[/tex]

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