shelby69 shelby69

12-01-2018
Mathematics

contestada

2x2+4x-5=0 using quadratic formula

Respuesta :

stevekimaz stevekimaz

15-01-2018

So solve for x? using the quadratic formula.
a = 2, b = 4, c = -5

x = (-b +/- [tex] \sqrt{b^{2}-4ac } [/tex])/2a
   = (-4 +/- [tex] \sqrt{16-4(2)(-5)} [/tex])/2(2)
   = (-4 +/- [tex] \sqrt{16+40} [/tex])/4
   = (-4 +/- 2[tex] \sqrt{14} [/tex])/4
   = (-4 +/- 2[tex] \sqrt{14} [/tex])/4
   = -1 +/- [tex] \sqrt{14} [/tex]/2

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