jennay2
jennay2
15-12-2015
Mathematics
contestada
3cubed-5[6-2 (9-2)squared]
Respuesta :
apologiabiology
apologiabiology
15-12-2015
so you want
[tex] 3^{3}-5(6-2(9-2)^{2}) [/tex]
pemdas
do 9-2 firtst
9-2=7
now we have
[tex] 3^{3}-5(6-2(7)^{2}) [/tex]
exponents
[tex] 3^{3} [/tex]=3 times 3 times 3=27
[tex] 7^{2} [/tex]=49
now we have
27-5(6-2(49))
do iner parenthasees multiplication
2(49)=98
now we have
27-5(6-98)
inner parenthasees
27-5(-92)
distribute (a(b+c)=ab+ac)
27-(-460)
27+460=487
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