davinioza
davinioza davinioza
  • 12-02-2018
  • Mathematics
contestada

A) 1

B) 6

C) 9

D) 18

A 1 B 6 C 9 D 18 class=

Respuesta :

choixongdong
choixongdong choixongdong
  • 12-02-2018
2 KZ = WZ
2(y + 1) = 3y
2y + 2 = 3y
y = 2
so
KZ = 2 + 1 = 3
WZ = 3(2) = 6

WK =  WZ + ZK
WK = 6 + 3
WK = 9

answer
C) 9
Answer Link
sqdancefan
sqdancefan sqdancefan
  • 12-02-2018
WZ = 2*ZK
3y = 2*(y +1) . . . . substitute given values
y = 2 . . . . . . . . . . subtract 2y

WK = WZ +ZK
WK = 3y +(y+1) = 3*2 +(2+1)
WK = 9 . . . . . . . . . matches selection C
Answer Link

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