briscosarg19 briscosarg19

13-02-2018
Mathematics

contestada

Solve the equation on the interval [0,2pi)

2cos² θ/2 -3cosθ=0

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tynollette tynollette

13-02-2018

to solve this problem, you first have to know the half angle identify of cosine.
cos(θ/2)=+/-√(1+cosθ)/2, so cos² (θ/2)=(1+cosθ)/2, and 2cos² (θ/2)=1+cosθ

2cos² (θ/2) -3cosθ=0
1+cosθ-3cosθ=0
2cosθ=1
cosθ=1/2
θ=π/3, or (5/3)π

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