ssepeda98
ssepeda98 ssepeda98
  • 15-01-2016
  • Mathematics
contestada

√y+7=y/6
I'm not sure how to solve this.

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Panoyin
Panoyin Panoyin
  • 15-01-2016
[tex]\sqrt{y + 7} = \frac{1}{6}y[/tex]
[tex](\sqrt{y + 7})^{2} = (\frac{1}{6})^{2}[/tex]
[tex]y + 7 = \frac{1}{36}[/tex]
[tex]y = -6\frac{35}{36}[/tex]
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