If an object is projected upward with an initial velocity of 125 125 ft per sec, its height h after t seconds is h equals negative 16 t squared plus 125 t h=−16t2+125t. Find the height of the object after 5 5 seconds.
for this problem all we need to do is ignore everything except the equation and the input (5.5)
so the steps for this problem are below we need to plug in 5.5 into our equation as it's our input of time to get our output of height [tex]t(5.5) = - 16(5.5) {}^{2} + 125(5.5)[/tex] after simplifying you get
remember to square the 5.5 first (order of operations)
[tex]t(5.5) = - 16(30.25) + 687.5[/tex]
simplify just a tad more and we get this as the final answer [tex]t(5.5) = - 484 + 687.5 = 203.5[/tex] [tex]203.5 \: ft[/tex]
