The balanced equation for the reaction between Na and H₂SO₄ is as follows; 2Na + H₂SO₄ ---> Na₂SO₄ + H₂ Stoichiometry of Na to H₂SO₄ is 2:1 the molar concentration of H₂SO₄ is 6.0 M This means that in 1 L of H₂SO₄ - there are 6.0 mol of H₂SO₄ Therefore in 750 mL - [tex] \frac{6.0 mol* 750 mL}{1000mL } [/tex] Number of H₂SO₄ moles reacted - 4.5 mol According to stoichiometry, 1 mol of H₂SO₄ reacts with 2 mol of Na Therefore 4.5 mol reacts with 2x4.5= 9 mol of Na Mass of Na reacted - 9 mol x 23 g/mol = 207 g of Na is required
