PinkPear160
PinkPear160 PinkPear160
  • 12-04-2018
  • Mathematics
contestada

The quadratic equation y=-x^2+2x-3, the axis of symmetry is x=1. What is the vertex?

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kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 21-03-2019

ANSWER

[tex](1,-2)[/tex]

EXPLANATION

The given quadratic equation is:

[tex]y = - {x}^{2} + 2x - 3[/tex]

The axis of symmetry of this parabola is

[tex]x = 1[/tex]

This is the also the x-coordinate of the vertex.

To find the y-coordinate of the vertex, substitute x=1 into the equation.

[tex]y = - {(1)}^{2} + 2(1)- 3[/tex]

[tex]y = - 1 + 2 - 3[/tex]

[tex]y = - 2[/tex]

The vertex is

(1,-2)

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