Thugnificent Thugnificent

15-04-2018
Mathematics

contestada

If a circle has a center at the point (3, 4) and goes through the point (6, 8), what is the radius?

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altavistard altavistard

15-04-2018

Start with the eqn of a circle with center at (h,k) and radius r:

(x-3)^2 + (y-4)^2 = r^2. Now replace x with 6 and y with 8:

(6-3)^2 + (8-4)^2 = r^2

3^2 + 4^2 = r^2 => r = 5.

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