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  • 11-10-2020
  • Mathematics
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Please help!! ASAP!! Math Help!k

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cromulent
cromulent cromulent
  • 11-10-2020

[tex]f(x) = 4x^3 + Ax^2 + 2x - 5[/tex]

[tex]f(2) = 5[/tex]

[tex]5 = 4 \cdot 2^3 + A \cdot 2^2 + 2 \cdot 2 - 5\\5 = 4 \cdot 8 + 4A + 4 - 5\\5 = 32 + 4A + 4 - 5\\5 - 32 - 4 + 5 = 4A\\-26 = 4A\\A = \frac{-26}{4} = -\frac{13}{2} = -6.5[/tex]

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