meredith48034
meredith48034 meredith48034
  • 15-10-2020
  • Mathematics
contestada

Find the value(s) of "k" that will cause the equation 4x^2 +kx + 4 to have one real solution.

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tramserran
tramserran tramserran
  • 15-10-2020

Answer:  k = {8, -8}

Step-by-step explanation:

In order for a quadratic equation to have exactly one solution, the discriminant must equal zero.       →        b² - 4ac = 0

  4x² + kx + 4 = 0

  ↓       ↓      ↓

a=4    b=k    c=4

b² - 4ac = 0

k² - 4(4)(4) = 0

k²             = 64

           k = √64

           k = ± 8

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