jessicadmart
jessicadmart
14-02-2017
Mathematics
contestada
how can i solve this trig identity??
Respuesta :
ramiroolivarez
ramiroolivarez
14-02-2017
hey there you just need to turn the one into (1+cosx)/(1`+cosx) and go from there
Answer Link
ItzStarzMe
ItzStarzMe
23-03-2022
Add
itional
Information
:
sin² θ + cos² θ = 1
sin² θ = 1 - cos²θ
sec²θ = 1 + tan²θ
cot²θ = cosec²θ - 1
★
Reciprocal
identities :-
[tex] \red{\boxed{sin θ = \dfrac{1}{cosecθ}}}[/tex]
[tex]\red{\boxed{cosec θ = \dfrac{1}{ sin θ}}}[/tex]
[tex]\red{\boxed{cos θ = \dfrac{1}{ sec θ}}}[/tex]
[tex]\red{\boxed{sec θ = \dfrac{1}{cos θ}}}[/tex]
[tex]\red{\boxed{tan θ = \dfrac{1}{ cot θ}}}[/tex]
[tex]\red{\boxed{cot θ = \dfrac{1}{tan θ}}}[/tex]
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